(7u+4)(2u^2-5u+3)=

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Solution for (7u+4)(2u^2-5u+3)= equation: 


Simplifying
(7u + 4)(2u2 + -5u + 3) = 0

Reorder the terms:
(4 + 7u)(2u2 + -5u + 3) = 0

Reorder the terms:
(4 + 7u)(3 + -5u + 2u2) = 0

Multiply (4 + 7u) * (3 + -5u + 2u2)
(4(3 + -5u + 2u2) + 7u * (3 + -5u + 2u2)) = 0
((3 * 4 + -5u * 4 + 2u2 * 4) + 7u * (3 + -5u + 2u2)) = 0
((12 + -20u + 8u2) + 7u * (3 + -5u + 2u2)) = 0
(12 + -20u + 8u2 + (3 * 7u + -5u * 7u + 2u2 * 7u)) = 0
(12 + -20u + 8u2 + (21u + -35u2 + 14u3)) = 0

Reorder the terms:
(12 + -20u + 21u + 8u2 + -35u2 + 14u3) = 0

Combine like terms: -20u + 21u = 1u
(12 + 1u + 8u2 + -35u2 + 14u3) = 0

Combine like terms: 8u2 + -35u2 = -27u2
(12 + 1u + -27u2 + 14u3) = 0

Solving
12 + 1u + -27u2 + 14u3 = 0

Solving for variable 'u'.

The solution to this equation could not be determined.

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